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The mass of a truck with its cargo is 1800 kg. The truck is coasting to the right with a speed of 10 m/s. As it coasts its cargo of mass 300 kg is lifted up out of the truck by a crane. What will the velocity of the truck be after its cargo is taken off?

Answer :

i would round it out to be 15 ms or 20 good luck 

Here we apply conservation of linear momentum. The momentum of the truck with cargo and without cargo remains constant. That is,

[tex] mv=m'v' [/tex].

Here [tex] m,v [/tex] are initial mass and velocity. [tex] m',v' [/tex] are final mass and velocity. Here [tex] m=1800,v=10 [/tex] and [tex] m'=1800-300=1500 [/tex].

The velocity of the truck be after its cargo is taken off is

[tex] v'=\frac{mv}{m'} \\
v'=\frac{1800*10}{1500} \\
v'=12 m/s [/tex]

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